Integrand size = 31, antiderivative size = 151 \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\left (2 a A b+a^2 B-b^2 B\right ) x-\frac {\left (b^2 B-a (2 A b+a B)\right ) \cot (c+d x)}{d}+\frac {\left (a^2 A-A b^2-2 a b B\right ) \cot ^2(c+d x)}{2 d}-\frac {a (2 A b+a B) \cot ^3(c+d x)}{3 d}-\frac {a^2 A \cot ^4(c+d x)}{4 d}+\frac {\left (a^2 A-A b^2-2 a b B\right ) \log (\sin (c+d x))}{d} \]
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Time = 0.48 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.161, Rules used = {3685, 3709, 3610, 3612, 3556} \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {\left (a^2 A-2 a b B-A b^2\right ) \cot ^2(c+d x)}{2 d}+\frac {\left (a^2 A-2 a b B-A b^2\right ) \log (\sin (c+d x))}{d}+x \left (a^2 B+2 a A b-b^2 B\right )-\frac {a^2 A \cot ^4(c+d x)}{4 d}-\frac {\left (b^2 B-a (a B+2 A b)\right ) \cot (c+d x)}{d}-\frac {a (a B+2 A b) \cot ^3(c+d x)}{3 d} \]
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Rule 3556
Rule 3610
Rule 3612
Rule 3685
Rule 3709
Rubi steps \begin{align*} \text {integral}& = -\frac {a^2 A \cot ^4(c+d x)}{4 d}+\int \cot ^4(c+d x) \left (a (2 A b+a B)-\left (a^2 A-A b^2-2 a b B\right ) \tan (c+d x)+b^2 B \tan ^2(c+d x)\right ) \, dx \\ & = -\frac {a (2 A b+a B) \cot ^3(c+d x)}{3 d}-\frac {a^2 A \cot ^4(c+d x)}{4 d}+\int \cot ^3(c+d x) \left (-a^2 A+A b^2+2 a b B+\left (b^2 B-a (2 A b+a B)\right ) \tan (c+d x)\right ) \, dx \\ & = \frac {\left (a^2 A-A b^2-2 a b B\right ) \cot ^2(c+d x)}{2 d}-\frac {a (2 A b+a B) \cot ^3(c+d x)}{3 d}-\frac {a^2 A \cot ^4(c+d x)}{4 d}+\int \cot ^2(c+d x) \left (b^2 B-a (2 A b+a B)+\left (a^2 A-A b^2-2 a b B\right ) \tan (c+d x)\right ) \, dx \\ & = -\frac {\left (b^2 B-a (2 A b+a B)\right ) \cot (c+d x)}{d}+\frac {\left (a^2 A-A b^2-2 a b B\right ) \cot ^2(c+d x)}{2 d}-\frac {a (2 A b+a B) \cot ^3(c+d x)}{3 d}-\frac {a^2 A \cot ^4(c+d x)}{4 d}+\int \cot (c+d x) \left (a^2 A-A b^2-2 a b B+\left (2 a A b+a^2 B-b^2 B\right ) \tan (c+d x)\right ) \, dx \\ & = \left (2 a A b+a^2 B-b^2 B\right ) x-\frac {\left (b^2 B-a (2 A b+a B)\right ) \cot (c+d x)}{d}+\frac {\left (a^2 A-A b^2-2 a b B\right ) \cot ^2(c+d x)}{2 d}-\frac {a (2 A b+a B) \cot ^3(c+d x)}{3 d}-\frac {a^2 A \cot ^4(c+d x)}{4 d}+\left (a^2 A-A b^2-2 a b B\right ) \int \cot (c+d x) \, dx \\ & = \left (2 a A b+a^2 B-b^2 B\right ) x-\frac {\left (b^2 B-a (2 A b+a B)\right ) \cot (c+d x)}{d}+\frac {\left (a^2 A-A b^2-2 a b B\right ) \cot ^2(c+d x)}{2 d}-\frac {a (2 A b+a B) \cot ^3(c+d x)}{3 d}-\frac {a^2 A \cot ^4(c+d x)}{4 d}+\frac {\left (a^2 A-A b^2-2 a b B\right ) \log (\sin (c+d x))}{d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 3.10 (sec) , antiderivative size = 180, normalized size of antiderivative = 1.19 \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {12 \left (2 a A b+a^2 B-b^2 B\right ) \cot (c+d x)+6 \left (a^2 A-A b^2-2 a b B\right ) \cot ^2(c+d x)-4 a (2 A b+a B) \cot ^3(c+d x)-3 a^2 A \cot ^4(c+d x)-6 \left ((a+i b)^2 (A+i B) \log (i-\tan (c+d x))+\left (-2 a^2 A+2 A b^2+4 a b B\right ) \log (\tan (c+d x))+(a-i b)^2 (A-i B) \log (i+\tan (c+d x))\right )}{12 d} \]
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Time = 0.28 (sec) , antiderivative size = 162, normalized size of antiderivative = 1.07
method | result | size |
derivativedivides | \(\frac {A \,a^{2} \left (-\frac {\left (\cot ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+B \,a^{2} \left (-\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}+\cot \left (d x +c \right )+d x +c \right )+2 A a b \left (-\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}+\cot \left (d x +c \right )+d x +c \right )+2 B a b \left (-\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )+A \,b^{2} \left (-\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )+B \,b^{2} \left (-\cot \left (d x +c \right )-d x -c \right )}{d}\) | \(162\) |
default | \(\frac {A \,a^{2} \left (-\frac {\left (\cot ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}+\ln \left (\sin \left (d x +c \right )\right )\right )+B \,a^{2} \left (-\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}+\cot \left (d x +c \right )+d x +c \right )+2 A a b \left (-\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}+\cot \left (d x +c \right )+d x +c \right )+2 B a b \left (-\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )+A \,b^{2} \left (-\frac {\left (\cot ^{2}\left (d x +c \right )\right )}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )+B \,b^{2} \left (-\cot \left (d x +c \right )-d x -c \right )}{d}\) | \(162\) |
parallelrisch | \(\frac {6 \left (-A \,a^{2}+A \,b^{2}+2 B a b \right ) \ln \left (\sec ^{2}\left (d x +c \right )\right )+12 \left (A \,a^{2}-A \,b^{2}-2 B a b \right ) \ln \left (\tan \left (d x +c \right )\right )-3 A \left (\cot ^{4}\left (d x +c \right )\right ) a^{2}+4 \left (-2 A a b -B \,a^{2}\right ) \left (\cot ^{3}\left (d x +c \right )\right )+6 \left (\cot ^{2}\left (d x +c \right )\right ) \left (A \,a^{2}-A \,b^{2}-2 B a b \right )+12 \cot \left (d x +c \right ) \left (2 A a b +B \,a^{2}-B \,b^{2}\right )+24 d \left (A a b +\frac {1}{2} B \,a^{2}-\frac {1}{2} B \,b^{2}\right ) x}{12 d}\) | \(170\) |
norman | \(\frac {\frac {\left (2 A a b +B \,a^{2}-B \,b^{2}\right ) \left (\tan ^{3}\left (d x +c \right )\right )}{d}+\left (2 A a b +B \,a^{2}-B \,b^{2}\right ) x \left (\tan ^{4}\left (d x +c \right )\right )-\frac {A \,a^{2}}{4 d}+\frac {\left (A \,a^{2}-A \,b^{2}-2 B a b \right ) \left (\tan ^{2}\left (d x +c \right )\right )}{2 d}-\frac {a \left (2 A b +B a \right ) \tan \left (d x +c \right )}{3 d}}{\tan \left (d x +c \right )^{4}}+\frac {\left (A \,a^{2}-A \,b^{2}-2 B a b \right ) \ln \left (\tan \left (d x +c \right )\right )}{d}-\frac {\left (A \,a^{2}-A \,b^{2}-2 B a b \right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d}\) | \(188\) |
risch | \(2 A a b x +B \,a^{2} x -B \,b^{2} x +\frac {2 i A \,b^{2} c}{d}+i A \,b^{2} x +\frac {4 i B a b c}{d}-i A \,a^{2} x +2 i B a b x -\frac {2 i a^{2} A c}{d}-\frac {2 i \left (6 i B a b \,{\mathrm e}^{6 i \left (d x +c \right )}+3 i A \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+6 i B a b \,{\mathrm e}^{2 i \left (d x +c \right )}-12 A a b \,{\mathrm e}^{6 i \left (d x +c \right )}-6 B \,a^{2} {\mathrm e}^{6 i \left (d x +c \right )}+3 B \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}-6 i A \,a^{2} {\mathrm e}^{2 i \left (d x +c \right )}-12 i B a b \,{\mathrm e}^{4 i \left (d x +c \right )}-6 i A \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}+24 A a b \,{\mathrm e}^{4 i \left (d x +c \right )}+12 B \,a^{2} {\mathrm e}^{4 i \left (d x +c \right )}-9 B \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}+6 i A \,a^{2} {\mathrm e}^{4 i \left (d x +c \right )}+3 i A \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}-6 i A \,a^{2} {\mathrm e}^{6 i \left (d x +c \right )}-20 A a b \,{\mathrm e}^{2 i \left (d x +c \right )}-10 B \,a^{2} {\mathrm e}^{2 i \left (d x +c \right )}+9 B \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+8 A a b +4 B \,a^{2}-3 B \,b^{2}\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{4}}+\frac {A \,a^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) A \,b^{2}}{d}-\frac {2 \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) B a b}{d}\) | \(447\) |
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Time = 0.27 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.26 \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {6 \, {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} \log \left (\frac {\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{4} + 3 \, {\left (3 \, A a^{2} - 4 \, B a b - 2 \, A b^{2} + 4 \, {\left (B a^{2} + 2 \, A a b - B b^{2}\right )} d x\right )} \tan \left (d x + c\right )^{4} + 12 \, {\left (B a^{2} + 2 \, A a b - B b^{2}\right )} \tan \left (d x + c\right )^{3} - 3 \, A a^{2} + 6 \, {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} \tan \left (d x + c\right )^{2} - 4 \, {\left (B a^{2} + 2 \, A a b\right )} \tan \left (d x + c\right )}{12 \, d \tan \left (d x + c\right )^{4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 313 vs. \(2 (136) = 272\).
Time = 1.85 (sec) , antiderivative size = 313, normalized size of antiderivative = 2.07 \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\begin {cases} \tilde {\infty } A a^{2} x & \text {for}\: c = 0 \wedge d = 0 \\x \left (A + B \tan {\left (c \right )}\right ) \left (a + b \tan {\left (c \right )}\right )^{2} \cot ^{5}{\left (c \right )} & \text {for}\: d = 0 \\\tilde {\infty } A a^{2} x & \text {for}\: c = - d x \\- \frac {A a^{2} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} + \frac {A a^{2} \log {\left (\tan {\left (c + d x \right )} \right )}}{d} + \frac {A a^{2}}{2 d \tan ^{2}{\left (c + d x \right )}} - \frac {A a^{2}}{4 d \tan ^{4}{\left (c + d x \right )}} + 2 A a b x + \frac {2 A a b}{d \tan {\left (c + d x \right )}} - \frac {2 A a b}{3 d \tan ^{3}{\left (c + d x \right )}} + \frac {A b^{2} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} - \frac {A b^{2} \log {\left (\tan {\left (c + d x \right )} \right )}}{d} - \frac {A b^{2}}{2 d \tan ^{2}{\left (c + d x \right )}} + B a^{2} x + \frac {B a^{2}}{d \tan {\left (c + d x \right )}} - \frac {B a^{2}}{3 d \tan ^{3}{\left (c + d x \right )}} + \frac {B a b \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{d} - \frac {2 B a b \log {\left (\tan {\left (c + d x \right )} \right )}}{d} - \frac {B a b}{d \tan ^{2}{\left (c + d x \right )}} - B b^{2} x - \frac {B b^{2}}{d \tan {\left (c + d x \right )}} & \text {otherwise} \end {cases} \]
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Time = 0.33 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.16 \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=\frac {12 \, {\left (B a^{2} + 2 \, A a b - B b^{2}\right )} {\left (d x + c\right )} - 6 \, {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + 12 \, {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} \log \left (\tan \left (d x + c\right )\right ) + \frac {12 \, {\left (B a^{2} + 2 \, A a b - B b^{2}\right )} \tan \left (d x + c\right )^{3} - 3 \, A a^{2} + 6 \, {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} \tan \left (d x + c\right )^{2} - 4 \, {\left (B a^{2} + 2 \, A a b\right )} \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{4}}}{12 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 435 vs. \(2 (145) = 290\).
Time = 1.18 (sec) , antiderivative size = 435, normalized size of antiderivative = 2.88 \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=-\frac {3 \, A a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 8 \, B a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 16 \, A a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 36 \, A a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 48 \, B a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 24 \, A b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 120 \, B a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 240 \, A a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 96 \, B b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 192 \, {\left (B a^{2} + 2 \, A a b - B b^{2}\right )} {\left (d x + c\right )} + 192 \, {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right ) - 192 \, {\left (A a^{2} - 2 \, B a b - A b^{2}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) + \frac {400 \, A a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 800 \, B a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 400 \, A b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 120 \, B a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 240 \, A a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 96 \, B b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 36 \, A a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 48 \, B a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 24 \, A b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 8 \, B a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 16 \, A a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, A a^{2}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4}}}{192 \, d} \]
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Time = 8.04 (sec) , antiderivative size = 182, normalized size of antiderivative = 1.21 \[ \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 (A+B \tan (c+d x)) \, dx=-\frac {{\mathrm {cot}\left (c+d\,x\right )}^4\,\left (\frac {A\,a^2}{4}+{\mathrm {tan}\left (c+d\,x\right )}^2\,\left (-\frac {A\,a^2}{2}+B\,a\,b+\frac {A\,b^2}{2}\right )-{\mathrm {tan}\left (c+d\,x\right )}^3\,\left (B\,a^2+2\,A\,a\,b-B\,b^2\right )+\mathrm {tan}\left (c+d\,x\right )\,\left (\frac {B\,a^2}{3}+\frac {2\,A\,b\,a}{3}\right )\right )}{d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )\right )\,\left (-A\,a^2+2\,B\,a\,b+A\,b^2\right )}{d}+\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (A-B\,1{}\mathrm {i}\right )\,{\left (b+a\,1{}\mathrm {i}\right )}^2}{2\,d}+\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,\left (A+B\,1{}\mathrm {i}\right )\,{\left (-b+a\,1{}\mathrm {i}\right )}^2}{2\,d} \]
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